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 Post subject: x is the sum of y consecutive integers
 Post Posted: Thu May 08, 2008 1:04 pm 
x is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integers, then each of the following could be true EXCEPT

1. x = w
2. x > w
3. x/y is an integer
4. w/z is an integer
5. x/z is an integer

Explanation given:
For any set of consecutive integers with an odd number of terms, the sum of the integers is always a multiple of the number of terms. For example, the sum of 1, 2, and 3 (three consecutives -- an odd number) is 6, which is a multiple of 3. For any set of consecutive integers with an even number of terms, the sum of the integers is never a multiple of the number of terms. For example, the sum of 1, 2, 3, and 4 (four consecutives -- an even number) is 10, which is not a multiple of 4.

The question tells us that y = 2z, which allows us to deduce that y is even. Since y is even, then the sum of y integers, x, cannot be a multiple of y. Therefore, x/y cannot be an integer; choice C is the correct answer.


Question:

Can you please explain another way to solve this problem? Is there another way to do it instead of plugging in numbers (which would take a long time in this case)?


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 Post subject: Re: x is the sum of y consecutive integers
 Post Posted: Wed May 14, 2008 12:20 am 
Anonymous wrote:
x is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integers, then each of the following could be true EXCEPT

1. x = w
2. x > w
3. x/y is an integer
4. w/z is an integer
5. x/z is an integer

Explanation given:
For any set of consecutive integers with an odd number of terms, the sum of the integers is always a multiple of the number of terms. For example, the sum of 1, 2, and 3 (three consecutives -- an odd number) is 6, which is a multiple of 3. For any set of consecutive integers with an even number of terms, the sum of the integers is never a multiple of the number of terms. For example, the sum of 1, 2, 3, and 4 (four consecutives -- an even number) is 10, which is not a multiple of 4.

The question tells us that y = 2z, which allows us to deduce that y is even. Since y is even, then the sum of y integers, x, cannot be a multiple of y. Therefore, x/y cannot be an integer; choice C is the correct answer.

Question: Can you please explain another way to solve this problem? Is there another way to do it instead of plugging in numbers (which would take a long time in this case)?


y = 2z
if z = 1, y 2
if z = 2, y = 4
if z = 3, y = 6
if z = 4, y = 8

so y is always even and average of even consecutive integers is always not an integer.

lets write down some even consecutive integers. suppose y = 4:

so the integers are: a, a+1, a+2, a+3
x = a + a+1 + a+2 + a+3
x = 4a + 6
so 4a+6 is not evenly divisible by 4. therefore x/y is not an integer...


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 Post subject: Re: x is the sum of y consecutive integers
 Post Posted: Wed May 14, 2008 11:36 pm 
Anonymous wrote:
Anonymous wrote:
x is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integers, then each of the following could be true EXCEPT

1. x = w
2. x > w
3. x/y is an integer
4. w/z is an integer
5. x/z is an integer

Explanation given:
For any set of consecutive integers with an odd number of terms, the sum of the integers is always a multiple of the number of terms. For example, the sum of 1, 2, and 3 (three consecutives -- an odd number) is 6, which is a multiple of 3. For any set of consecutive integers with an even number of terms, the sum of the integers is never a multiple of the number of terms. For example, the sum of 1, 2, 3, and 4 (four consecutives -- an even number) is 10, which is not a multiple of 4.

The question tells us that y = 2z, which allows us to deduce that y is even. Since y is even, then the sum of y integers, x, cannot be a multiple of y. Therefore, x/y cannot be an integer; choice C is the correct answer.

Question: Can you please explain another way to solve this problem? Is there another way to do it instead of plugging in numbers (which would take a long time in this case)?


y = 2z
if z = 1, y 2
if z = 2, y = 4
if z = 3, y = 6
if z = 4, y = 8

so y is always even and average of even consecutive integers is always not an integer.

lets write down some even consecutive integers. suppose y = 4:

so the integers are: a, a+1, a+2, a+3
x = a + a+1 + a+2 + a+3
x = 4a + 6
so 4a+6 is not evenly divisible by 4. therefore x/y is not an integer...


wow i forgot to put my username.


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 Post subject:
 Post Posted: Fri May 30, 2008 5:34 am 
Offline
ManhattanGMAT Staff


Posts: 386
UPA's solution is akin to how I would solve it as well. I usually find it helpful to express consecutive sets using variables like a, a+1, a+2, etc. and seeing what insights I can draw from that analysis.

Rey


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 Post subject: Re: x is the sum of y consecutive integers
 Post Posted: Sun Sep 11, 2011 11:51 pm 
Offline
Students


Posts: 12
average of even consecutive integers is always not an integer.

Is this a rule?

eg.
2+4+6/3 = 12/3 = 4

Can some one please explain the statement given above.

Thanks


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 Post subject: Re: x is the sum of y consecutive integers
 Post Posted: Mon Sep 12, 2011 12:26 am 
Offline
Students


Posts: 55
viv09 wrote:
average of even consecutive integers is always not an integer.

Is this a rule?

eg.
2+4+6/3 = 12/3 = 4

Can some one please explain the statement given above.

Thanks


what he meant is

average of even "numbers" of consecutive numbers is not an interger

for example
1 + 2 / 2 OR 1 + 2 + 3 + 4 / 4 OR 1 + 2 + 3 + 4 + 5 + 6 / 6

are never integers


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 Post subject: Re: x is the sum of y consecutive integers
 Post Posted: Mon Sep 12, 2011 9:42 pm 
Offline
Students


Posts: 12
oh, I think I got caught up in the words... Thanks!!


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 Post subject: Re: x is the sum of y consecutive integers
 Post Posted: Mon Oct 17, 2011 12:31 am 
Offline
ManhattanGMAT Staff


Posts: 1857
Great! :-)

_________________
Jamie Nelson
ManhattanGMAT Instructor


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