 | Word Translation Problem (Percents) from GMATPrep CAT |  |
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iil-london
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Posted: Mon Mar 24, 2008 8:49 am |
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Each person in a certain group supports only one of two candidates R and T. Of the people in the group, 45 percent support Candidate R and the rest support Candidate T. How many people in the group are in favor of a flat tax ?
(1) Of the people in the group who support Candidate R, 58 percent are in favor of flat tax
(2) Of the people in the group who support Candidate T, 22 are in favor of a flat tax.
Here's my working for this problem:
Lets assume no. of people in group = 100.
R supporters = 45 (45% of 100)
T supporters = 55 (55% ("the rest" of 100)
(1) 58% of 45 -> INSUFF ... as this only gives us number of people in favor of flat tax from the group supporting candidate R. We also need to know how many of candidate T's supporters are in favor of flat tax, to determine how many people in the group are in favor of flat tax.
(2) Of the people in the group supporting Candidate T (55) ... 22 are in favour of flat tax. -> INSUFF ... this doesnt give us information about Candidate R's supporters.
(1) and (2) ... we have both candidate R's flat tax supporters (58% of 45), and candidate T's flat tax supporters (22), and hence the total number of people in the group in favor of a flat tax is (0.58*45) + 22. SUFF
So my working points to the answer as being C.
However the this is coming out as incorrect. WHY? where am I going wrong here ? I suspect I am making a simple mistake and falling into a trap somewhere.
Thanks in advance
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iil-london
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Posted: Mon Mar 24, 2008 11:59 am |
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Hi folks ... ignore my last question. I have found the "simple" mistake I was making ! I shouldnt have plugged in numbers !
(1) Of the people in the group who support Candidate R, 58 percent are in favor of flat tax
We dont know exactly how many people are supporting R. We only know it is 45% of a x (where x is the number of people in the group).
So this means the answer is E.
Thanks.
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Ron Purewal
MGMAT STAFF
| Joined: 08 Oct 2007 |
| Posts: 2295 |
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Posted: Fri Mar 28, 2008 11:25 pm |
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sounds like you're on your way. if you have any other questions about this problem, feel free to post them.
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