StaceyKoprince wrote:
This is essentially a sequence problem in disguise. Let x = amount of yearly growth, in feet.
Yr0 = 4
Yr1 = 4+x
Yr2 = 4+x+x=4+2x
Yr3 = 4+x+x+x=4+3x
Yr4 = 4+x+x+x+x=4+4x
Yr5 = 4+x+x+x+x+x=4+5x
Yr6 = 4+x+x+x+x+x+x=4+6x
We are told the amount at the end of Year 6 is 6/5 of the amount at the end of year 4. Thus we can write:
4+6x = 6/5 (4+4x)
5(4+6x) = 6(4+4x)
20+30x = 24+24x
6x=4
x=2/3
I never understood any formula in these stuff, Stacey you nailed it. Thanks!!!