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 Post subject: What is the remainder
 Post Posted: Sun Aug 14, 2011 5:52 pm 
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Students


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What is the remainder when the positive integer n is divided by the positive integer k, where k>1?

1) n=(k+1)^3

2) K=5


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 Post subject: Re: What is the remainder
 Post Posted: Mon Aug 15, 2011 3:05 am 
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ManhattanGMAT Staff


Posts: 7146
shady320 wrote:
What is the remainder when the positive integer n is divided by the positive integer k, where k>1?

1) n=(k+1)^3

2) K=5


(1)
multiply out (k+1)^3 = k^3 + 3(k^2) + 3k + 1.
all of these terms are multiples of k (which don't contribute to the remainder upon division by k) except for the last one, so the remainder must be 1.

(2)
there is no information about n, so this statement is insufficient.

so (a).

--

also note that you should be extremely reluctant to pick answer choice (c) on this problem -- that answer choice is a definite “trap answer”. i.e., it's far too easy -- it actually gives you numerical values of the two variables -- and it doesn't make any use of the fact that the question itself is about remainders.
so, if you can eliminate statement 2 (which shouldn't be that hard) and then dismiss (c) as a trap answer, the only choice that's actually left at that point is the correct answer!


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 Post subject: Re: What is the remainder
 Post Posted: Fri Aug 26, 2011 12:25 am 
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Location: San Francisco
n/k = (k+1)^3 / K
= (k^3 + 1^3) / k
= k^2 + 1/k

remainder of 1

not sure if this would work for all remainders or just lucky cause it is 1 (1^3 = 1)


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 Post subject: Re: What is the remainder
 Post Posted: Fri Aug 26, 2011 11:37 am 
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Course Students


Posts: 76
sfbay wrote:
n/k = (k+1)^3 / K
= (k^3 + 1^3) / k
= k^2 + 1/k

remainder of 1

not sure if this would work for all remainders or just lucky cause it is 1 (1^3 = 1)

Not correct.

(k+1)^3 / K is not (k^3 + 1^3) / k. When you expand, you will get k^3 + 3(k^2) + 3k + 1.


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 Post subject: Re: What is the remainder
 Post Posted: Sat Sep 03, 2011 9:01 pm 
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ManhattanGMAT Staff


Posts: 7146
mithunsam wrote:
Not correct.

(k+1)^3 / K is not (k^3 + 1^3) / k. When you expand, you will get k^3 + 3(k^2) + 3k + 1.


yes, thanks.

also note that this result is in my post, directly above the incorrect post.

read the thread, people!


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