If there are 2 corresponding angle triangles and one has an area twice the other. then in therms of s (smaller triangle's base) what is S (bigger triangle's base) a. √ 2s /2 b. √ 3s/2 c. √2s d. √ 3s e. 2s
I assume 2 corresponding angled traingles mean that 2 angles are corresponding in both triangles. Thus the third angle also has to be same. Therefore, by AAA (Angle-Angle-Angle) rule we can prove both the triangles are similar in nature.
Furthermore just by heart this rule ( It can be proven)
If two similar triangles have sides in the ratio a/b , then their areas are in the ratio (a^2)/(b^2)----(1)
Coming to the problem, Let's assume the area of the smaller triangle is x Therefore, the area of the larger triangle is 2x
Substituting this information in (1) we get, (s^2)/(S^2)=x/2x
here's a big fat existing thread on this problem: post19973.html
Page 1 of 1 [ 3 posts ]
Who is online
Users browsing this forum: No registered users and 1 guest
You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot post attachments in this forum
Learn concepts that are most likely to appear on the GMAT.
Study Hall: Thursdays with Ron
Every other Thursday, join Ron Purewal for an hour and a half study session. Submit your questions online beforehand and Ron will handpick ones to teach during the session.
Answer our weekly GMAT math problem for a chance to win! Each week one correct answer is chosen to win guides and more. The more people enter, the better the prize!
Do you have what it takes to become a Manhattan GMAT instructor? If you have a 99th percentile score and prior teaching experience, apply here to make $100 an hour.
Not quite ready to be an instructor yourself? If you refer a friend to us and we hire them, we'll give you $1000.