Problem Source: OG 11th edition. Problem # 202

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Can someone please explain why the answer for this problem is “B”

Thank you very much in advance.

[deleted - OG question]

Best option is assume a value for r.
Ler r=2

V = 1/(2*2)^3
V = 1/64 ------(1)

Now what happens when r is halved . i.e r = 1
V = 1/(2*1)^3
V = 1/8 -------(2)


Question askes us what should we multiple eqution 1 to get equation 2
Clearly (1/8) /(1/64) = 8

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