For every positive even integer n, the function h(n) is defined to be the product of all the even integers from 2 to n, inclusive. If p is the smallest prime factor of h(100) +1, then p is:
A) btwn 2 and 10 B) btwn 10 and 20 C) btwn 20 and 30 D) btwn 30 and 40 E) greater than 40
From that we could logically deduce that if the above value h(100) + 1 has a prime factor it should be greater then 47 and that value would be the smallest prime factor (the firs t one). It is evident that all the prime factors from 2 thru 47 DO NOT divide h(100) + 1.
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