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* Question

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jasonandsamantha
 Post subject: * Question
 Post Posted: Mon Nov 08, 2010 10:46 am 
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Students


Posts: 1
Hello, can anyone provide assitance?

For all numbers x such that x does not equal 1, if g(x) is defined by g(x) =x^2 + 2/x-1, then (1/g(2))(1/g(x))? The correct answer is x-1/6(x^2) + 2.

Thank you.
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kaveri_princess
 Post subject: Re: Question
 Post Posted: Tue Nov 09, 2010 12:29 am 
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Students


Posts: 5
If g(x) = g(x) =x^2 + 2/x-1
Then 1/g(x) = x-1/x^2 + 2

g(2) = 2^2 + 2/2-1 = 4+2/1 = 6

1/g(2) = 1/6

Now (1/g(2))(1/g(x)) = (1/6)(x-1/x^2 + 2) =
x-1/6(x^2) + 2
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RonPurewal
 Post subject: Re: Question
 Post Posted: Fri Nov 12, 2010 7:37 pm 
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ManhattanGMAT Staff


Posts: 7146
hello --

please follow the forum rules!

if this problem is from the GMAT PREP SOFTWARE (note those are the only problems allowed in this folder), then, per the forum rules, please post the entire PROBLEM, with ALL answer choices.

please do so within 1 week, or else we will delete the thread on the next pass through.

thanks!
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