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Question on VICs

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casey.chopek
 Post subject: Question on VICs
 Post Posted: Tue Jun 02, 2009 10:23 pm 
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Course Students


Posts: 9
Hey Guys,

In the Eq, Ineq, VICs book, I am working through the chapter on VICs. In the 'Algebraic VIC Example' Section on p. 118 it simplifies the term to this point:

ab-2=144/cd - 2

I understand this. However, the next step is:

ab-2=(144/cd)-(2cd/cd) then ab-2=(144-2cd)/cd

I can't seem to recall the algebraic rule that supports these two steps. Can someone refresh my memory?

I'd greatly appreciate it!

Thanks!
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casey.chopek
 Post subject: Re: Question on VICs
 Post Posted: Thu Jun 04, 2009 9:24 am 
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Course Students


Posts: 9
Nevermind. Today I get this. Must've been the late hour on Sunday! Math is hard at night! :)
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esledge
 Post subject: Re: Question on VICs
 Post Posted: Tue Jul 14, 2009 5:07 pm 
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ManhattanGMAT Staff


Posts: 901
Location: St. Louis, MO
No kidding! Sleep deprivation and math ability are inversely correlated, I think.

But for the benefit of anyone else reading this...
casey.chopek wrote:
ab-2=(144/cd)-(2cd/cd) then ab-2=(144-2cd)/cd

I can't seem to recall the algebraic rule that supports these two steps. Can someone refresh my memory?

...the rule is that when adding or subtracting fractions, and the denominator is the same, you just add or subtract the respective numerators.

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Emily Sledge
Instructor
ManhattanGMAT
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