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 Post subject: question of advanced ds principle
 Post Posted: Fri Sep 09, 2011 5:02 pm 
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Students


Posts: 27
is the integer n odd ?
1) n(n-2) is not a multiple of 4.
2)n is a multiple of 3

hey the answer given is A , but what if n=2, then the n(n-2) is not a multiple of 4 and n is even ......
so how could A be the answer


Last edited by hemant.rao110 on Sat Sep 10, 2011 3:57 pm, edited 1 time in total.

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 Post subject: Re: question of advanced ds principle
 Post Posted: Fri Sep 09, 2011 5:21 pm 
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Course Students


Posts: 76
0 is a multiple of every number. Therefore, n cannot be 2.


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 Post subject: Re: question of advanced ds principle
 Post Posted: Sat Sep 10, 2011 10:05 am 
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Students


Posts: 27
0 is the multiple of every no. can u explain


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 Post subject: Re: question of advanced ds principle
 Post Posted: Sun Sep 11, 2011 10:21 am 
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Course Students


Posts: 76
For two numbers a and b, we say that b is a multiple of a if b = n * a, for some integer n.

For example, 27 is a multiple of 3 because 27 = 9 * 3. Here, a = 3, b = 26, and n = 9.

For 0, this condition satisfies for any number of a, when n=0.
0 = 0 * a, where a can be any integer.


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 Post subject: Re: question of advanced ds principle
 Post Posted: Sat Sep 17, 2011 11:23 pm 
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ManhattanGMAT Staff


Posts: 1857
mithunsam wrote:
For two numbers a and b, we say that b is a multiple of a if b = n * a, for some integer n.

For example, 27 is a multiple of 3 because 27 = 9 * 3. Here, a = 3, b = 26, and n = 9.

For 0, this condition satisfies for any number of a, when n=0.
0 = 0 * a, where a can be any integer.


Correct. 0 is considered a multiple of every positive integer.

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Jamie Nelson
ManhattanGMAT Instructor


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 Post subject: Re: question of advanced ds principle
 Post Posted: Sun Sep 18, 2011 8:22 pm 
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Students


Posts: 27
thank you jnelson and mithunsam


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 Post subject: Re: question of advanced ds principle
 Post Posted: Sat Oct 15, 2011 10:11 pm 
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ManhattanGMAT Staff


Posts: 1857
You are most welcome! :-)

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Jamie Nelson
ManhattanGMAT Instructor


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