accounts wrote:
We need equal number of cheese and fruits to make a platter. This can be done when
(1 type of cheese and 1 type of fruit) OR (2 type of cheese and 2 type of fruits)
Note: as types of fruits are 2 and types of cheese 6 ... fruits become the deciding factor.
( 6C1 X 2C1) OR ( 6C2 x 2C2 )
(6*2) + (15 x1 )
= 27 => E
this works.
as an alternative, note that you should easily be able to LIST the possibilities in the time given, and then COUNT the items in your list. (to facilitate this, it's best to call the cheeses 1, 2, 3, 4, 5, 6 and the fruits 1 and 2.)
try making this list; make sure that you can do so in well under the two-minute guideline.