A man chooses an outfit from 3 different shirts, 2 different pairs of shoes, and 3 different pants. If he randomly selects 1 shirt, 1 pair of shoes, and 1 pair of pants each morning for 3 days, what is the probability that he wears the same pair of shoes each day, but that no other piece of clothing is repeated?
A (1/3)^6 x (1/2)^3
B (1/3)^6 x (1/2)
C (1/3)^4
D (1/3)^2 x (1/2)
E 5(1/3)^2
ps63739
Post subject: Re: Probability question w/ exponents
Day 1 (favourable outcome) - He can select shoes two ways, Shirts and Pants each 3 ways = 2*3*3. Total number of outcomes = 2*3*3 So P(Day1) = 2*3*3/2*3*3 = 1 Day 2 (Favourable outcomes) - He can select shoes 1 (he has to wear the same shoe) way and select the pants and shirts 2 ways each (as he cannot wear the Shirt and Pant he wore Day1) = 1*2*2 Total outcomes = 2*3*3
So P(Day2) = 1*2*2/2*3*3 = 2/9. Day 3 - in the similar fashion P(day3) = 1/18
Now probability here will be multiplied.
Total probability will be = P(Day1) happens and P(Day2) happens and P(Day3) happnes.
That gives P= 1*(2/9)*(1/18) = 1/3^4.
Ben Ku
Post subject: Re: Probability question w/ exponents
Please cite the source (author) of this problem. We cannot reply unless a source is cited (and, if no source is cited, we will have to delete the post!). Thanks.
_________________ Ben Ku Instructor ManhattanGMAT
shalinibhatia15
Post subject: Re: Probability question w/ exponents
Please cite the source (author) of this problem. We cannot reply unless a source is cited (and, if no source is cited, we will have to delete the post!). Thanks.
mschwrtz
Post subject: Re: Probability question w/ exponents
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