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| Super Pythagorean??? |
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KTsincere
Guest
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Can someone explain the Super Pythagorean (when to use it, why, how)????
I'm a bit confused.... Thanks a lot |
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Ron Purewal
MGMAT STAFF
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the rule in sudhan's post is for real, but it's not anything you'll need for the gmat. the gmat doesn't require any trigonometry; the closest you'll get is 30-60 and 45-45 right triangles, but those can be handled via memorized templates (i.e., you don't have to use trig functions to solve them if you can remember the 1-1-root(2) and 1-root(3)-2 templates).
-- presumably, 'super pythagorean' refers to the following rule (which i myself refer to as 'p.t. deluxe' in class - sudhan, you should remember this if you're the same sudhan who took my virtual class recently): if D is the MAIN DIAGONAL OF A BOX whose length is L, width is W, and height is H, then: D^2 = L^2 + W^2 + H^2 or, D = root(L^2 + W^2 + H^2) notice that the first version is exactly the same as the pythagorean theorem with one additional term tacked onto it; hence the name 'super pythagorean' or 'p.t. deluxe'. if you ever need to find a diagonal distance in three dimensions, this is the formula to use. |
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Sudhan
Guest
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Thanks Ron. Now I remember you taught this formula in the class.
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KTsincere
Guest
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Thanks for the clarification... So just to make sure I understand, the main diagonal of a box is the longest diagonal correct?
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Sudhan
Guest
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yes.
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Ron Purewal
MGMAT STAFF
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yeah. you might know this already, but, full disclosure: there are actually 4 main diagonals, all of which have the same length. it's difficult to describe this without a diagram, but imagine that the sides of the box face north, east, south, and west. then the main diagonals run from: top NW to bottom SE top NE to bottom SW top SW to bottom NE top SE to bottom NW they're all the same length, and they're all longer than anything else you can draw in the box. |
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| Super Pythagorean??? |
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