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| EIVs Question Bank - Q3 AB>CD |
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Stacey Koprince
MGMAT STAFF
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Please post the complete text of the question, including answers. I can't figure out what is and isn't true if I can't see the answers I'm supposed to be evaluating... :)
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Guest
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Apologies Stacy ... here's the question in FULL:
If ab > cd and a, b, c and d are all greater than zero, which of the following CANNOT be true? (A) c > d (B) d > a (C) b/c < d/a (D) a/c > d/b (E) (cd)^2 < (ab)^2 The solution in the Question bank suggests going through each answer choice and plugging-in numbers. But I am keen to find out if there is another approach to tackle this type of question ? Thanks in advance. |
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Rey Fernandez
MGMAT STAFF
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You can reason your way through this one without plugging in numbers: A - Given ab > cd, on the right side of the inequality, one of three things can be happening: c > d, c = d, or c < d. B - Similar to A, but about the left side. C - If you divide both sides by c and by a, you get b/c > d/a. The inequality sign is facing the other way. C is not possible. D - Here, divide both sides by c and by b and you get a/c > d/b. E - Square both sides of the inequailty ab > cd and you wind up with the expression in answer choice E. Rey |
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| EIVs Question Bank - Q3 AB>CD |
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