Dear friends and moderators,

I didn't even know how to begin the following question:

If y > 0, what is the value of x?
1. |x - 3| > y
2. |x - 3| < - y

OA: B

Kindly explain.
Thanks
KH

Dear friends

After staring at the question for about half hour or so, I have come up with a solution. Kindly correct me if wrong.

If y > 0, what is the value of x?

1. |x - 3| > y
Taking numbers:
x: -2, 1 both can satisfy the above equation. Insufficient.

2. |x - 3| < - y
Since |x-3| is an absolute value, the smallest it can go is 0.
And since y is given to be >0, thus - y will give a negative value which will cause the equation to fall apart unless it is 0.

so |x-3| = 0.
x = 3.

Fundamentally sound?

Thanks
KH

looks good.

incidentally, you wrote the inequality signs as strict inequality (< and >) instead of weak inequality (< and >) this time, a condition that would actually render the problem impossible. if the problem is as written in the first post, then this solution is perfect.

Yes Ron
The inequality signs follow the 1st post.

1. |x - 3| > y
2. |x - 3| < - y

Thanks
KH