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| First and Second Degree Equations |
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KTsincere
Guest
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First: In your question you asked how can A(B+C) + D(B+C) = (A+D) + (B+C)... You made a typo it should read =(A+D)(B+C) There is no addition sign between (A+D) and (B+C)... its multiplication.
If you foil (A+D)(B+C) --> AB + AC +DB + DC ... this is the orignal equation just in a different order OR if you don't like to "FOIL" try this method you could use the vics method and assign each letter a value (A=2, B=3, C=4, D=5): A(B+C) + D(B+C) --> 2(3+4) + 5(3+4) = 2(7)+5(7) = 14+35 =49 (A+D)(B+C) --> (2+5) (3+4) = (7)(7) = 49 Hope this helps. KT |
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