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| Root Strategy exercise 14 page 67 chapter 6 |
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Stacey Koprince
MGMAT STAFF
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You are trying to add the x's and y's individually without regard to the fact that there are two separate terms with multiplied variables. Can't do that.
Try this analogous situation: xy + 2xy does this equal 3x + 2y? No. The first term has one "xy" and the second term has two "xy"s so there are a total of three "xy"s xy + 2xy = 3xy Same thing in the problem above: (x^2*y^3) + 3(x^2*y*3) First, I have one of these "x^2*y^3" terms and then I have three more, so I have four total (x^2*y^3) + 3(x^2*y*3) = 4(x^2*y*3) Put that all under a square root sign: pull the 4 out to get a 2 pull the x^2 out to get an x pull a y^2 out to get a y one y is still stuck under the square root sign SQRT 4*x^2*y*3 = 2xySQRTy |
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| thanks |
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fang6
Guest
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Stacey many thanks for your help with this problem I perfectly understand my mistake now ! THANK YOU !
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Stacey Koprince
MGMAT STAFF
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you're welcome!
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| Root Strategy exercise 14 page 67 chapter 6 |
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