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Root Strategy exercise 14 page 67 chapter 6
fang6
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Hello,

I am working on exercise 14 of number properties guide (roots page 67) and I am having difficulties simplifying the following :
SQRT X^2 * Y^3 + 3X^2* Y^3

when I simplify i find this result :

1) SQRT 4X^2 + 2Y^3

and i simplify to get this final result:

2) 2XY*SQRT 2Y

However the answer in the book is

2XY*SQRT Y

so it seems that the problem is with simplifying the

2Y^3

I would very much appreciate some help with understanding what I'm doing wrong here.

thanks

:idea:
Stacey Koprince
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Joined: 06 Mar 2007
Posts: 2439
Location: San Francisco
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You are trying to add the x's and y's individually without regard to the fact that there are two separate terms with multiplied variables. Can't do that.

Try this analogous situation:
xy + 2xy
does this equal 3x + 2y? No. The first term has one "xy" and the second term has two "xy"s so there are a total of three "xy"s
xy + 2xy = 3xy

Same thing in the problem above:
(x^2*y^3) + 3(x^2*y*3)
First, I have one of these "x^2*y^3" terms and then I have three more, so I have four total
(x^2*y^3) + 3(x^2*y*3) = 4(x^2*y*3)

Put that all under a square root sign:
pull the 4 out to get a 2
pull the x^2 out to get an x
pull a y^2 out to get a y
one y is still stuck under the square root sign

SQRT 4*x^2*y*3 = 2xySQRTy
thanks
fang6
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Stacey many thanks for your help with this problem I perfectly understand my mistake now ! THANK YOU !
Stacey Koprince
MGMAT STAFF

Joined: 06 Mar 2007
Posts: 2439
Location: San Francisco
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you're welcome!
Root Strategy exercise 14 page 67 chapter 6
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