ghong14 wrote:
Is x·|y| > y^2?
(1) x > y
(2) y > 0
The correct answer to this question is C. However I don't understand why we will need statement 2 for the statement to be sufficient. Here no matter what happens to Y on the left side is still postive. For example if y=-2 the |-2|=2 so when you divide that to the other side the signs do not flip right? Because when you are dividing by a negative absolute value such as |-2| are you dividing by its postivie absolute value or its negative value?
Let's test it out! Okay, statement 1 says that x > y. Let's test two cases:
x=3
y=2
Is 3* |2| > (2)^2? Is 6 > 4? Answer here is YES.
Now let's test out some negative numbers:
x=-2
y=-3
Is -2 * |-3| > (-3)^2? Is -6 > 9? Answer here is NO
Once I have a yes and a no, statement 1 has been shown to be not sufficient. Notice, the left side is not necessarily positive because x and y *could be* negative. :-)