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GMAT Prep Math zy < xy < 0 |x-z| + |x| = |z|
TheChakra
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I cannot find the GMAT Prep Math folder, so I am posting the question here.

If zy < xy < 0, is |x-z| + |x| = |z|?

1. z < x
2. y < 0

Knowing the answer, I can try values and confirm the answer. But, would like to know if anyone was able to rephrase the questions to be a little more helpful?

The answer is D
Re: GMAT Prep Math zy < xy < 0 |x-z| + |x| = |z|
TheChakra
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TheChakra wrote:
I cannot find the GMAT Prep Math folder, so I am posting the question here.

If zy < xy < 0, is |x-z| + |x| = |z|?

1. z < x
2. y < 0

Knowing the answer, I can try values and confirm the answer. But, would like to know if anyone was able to rephrase the questions to be a little more helpful?

The answer is D


BTw, This is the best I could come up with ..

Multiply |y| across so the question then is is |xy-zy| = |zy| - |xy|

There are multiple scenarios here (xy - zy < 0 and > 0), but the only scenario that doesn't break xy<xy<0 is

xy - zy > 0, zy < 0, xy < 0

--> xy > zy , zy < 0, xy < 0

The only way you can satisfy all of the above is when z < x or y < 0 , which is the answer
Tough to think like solution
y
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Given solution looks good. But it is very hard to think like that. I did not find a standard route to achieve the solution like this.
Guest83
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I may be way off here, let me know what you guys think.

Firstly, since both ZY and XY are both less than 0, this implies that Z and X are both negative or positive (depending on value of y)

if Y is negative:
Z and X are both positive. Since ZY < XY, this means X<Z.

if Y is positive:
Z and X are both negative. Since ZY < ZX, this means X>Z.


Now, statement 1 says that Z<X. This means that Y is positive.

|X-Z| + |X| = |Z| -> Z-X + X = Z -> YES


Statement 2:
Y < 0. This implies that X<Z.


|X-Z| + |X| = |Z| -> X-Z + X = Z -> NO


Therefore, both statements are sufficient.

Does this make sense?
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TheChakra
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Guest83 wrote:
I may be way off here, let me know what you guys think.

Firstly, since both ZY and XY are both less than 0, this implies that Z and X are both negative or positive (depending on value of y)

if Y is negative:
Z and X are both positive. Since ZY < XY, this means X<Z.

if Y is positive:
Z and X are both negative. Since ZY < ZX, this means X>Z.


Now, statement 1 says that Z<X. This means that Y is positive.

|X-Z| + |X| = |Z| -> Z-X + X = Z -> YES


Statement 2:
Y < 0. This implies that X<Z.


|X-Z| + |X| = |Z| -> X-Z + X = Z -> NO


Therefore, both statements are sufficient.

Does this make sense?

this is good.
Guest



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Hi can someone tell me the best way to tackle absolute value problems for data sufficiency.I know we should solve for X>0 and X<0.Is there an example someone could provide or an approach which is beneficial

Thanks
Ron Purewal
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Joined: 08 Oct 2007
Posts: 2199

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Anonymous wrote:
Hi can someone tell me the best way to tackle absolute value problems for data sufficiency.I know we should solve for X>0 and X<0.Is there an example someone could provide or an approach which is beneficial

Thanks


well, there are different breeds of absolute value problems, so (as usual) there's no one neat, solid answer to a question like that. however:
* if a problem contains the symbols "> 0" or "< 0" at any point, you can rest assured that the crux of the problem involves the signs of quantities. (the problem in this thread is a perfect example.)
if you encounter such a problem, you should immediately devote all of your energy to rephrasing the question prompt and/or statements to equivalent formulations involving 'positive'/'negative'.

for instance, if you see
zy < xy < 0
you should think:
* z and x have the same sign
* y must have the opposite of whatever sign those two have
* therefore, (x y z) is either (+ - +) or (- + -)

that sort of reasoning will be an excellent start. from there, there's no telling which way the wind will blow - just study your number properties, and you should be able to figure out the rest.

oh yeah, you should avoid 'solving' if at all possible: you should try to think in the abstract about the signs of the numbers, and about the situation resulting from each possible combination of signs. if that sort of reasoning gets you nowhere, then try plugging in numbers and solving as plan b.
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DLALL2001@YAHOO.COM
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Hi MG, i am new on this forum. i have taken 2 of the practice tests till now and scored 540 in the first one and 630 in the second (42Q and 32V). i feel i could have done much better as i believe i didnt pace my self well during the test. i have taken all the manhattan books and they have been very helpful in clearing the concepts.
i will be taking my gmat the next month. Can you pls advice me what should be my startegy this month to increase my score to 650+. Also would it also be possible for you to kindly access my tests and advice on the areas i need to concentrate on. Since i am working i am only able to study at night for 2-3 hrs. In Verbal i just not able to score on CR. Especially the BOLD question types. Can anyone pls advice on how to attempt these type of questions.

thanks
deepti
Stacey Koprince
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Joined: 06 Mar 2007
Posts: 2590
Location: San Francisco
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Hi, Deepti, welcome! I responded to your question in the general questions thread. Please take a moment to look at the forum guidelines and other "read me" posts at the tops of the folders. Those should give you a good orientation on how to use the forums.
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guest11
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Guest83 wrote:
I may be way off here, let me know what you guys think.

Firstly, since both ZY and XY are both less than 0, this implies that Z and X are both negative or positive (depending on value of y)

if Y is negative:
Z and X are both positive. Since ZY < XY, this means X<Z.

if Y is positive:
Z and X are both negative. Since ZY < ZX, this means X>Z.


Now, statement 1 says that Z<X. This means that Y is positive.

|X-Z| + |X| = |Z| -> Z-X + X = Z -> YES


Statement 2:
Y < 0. This implies that X<Z.


|X-Z| + |X| = |Z| -> X-Z + X = Z -> NO


Therefore, both statements are sufficient.

Does this make sense?


Close.

From the question:
zy < xy < 0



Implies:
1. Since zy and xy are < 0 , then if y > 0, z < 0 and x < 0, and if y < 0, then x > 0 and z > 0.
2. If y > 0
-- divide by y, no change in sign, so z < x
3. If y < 0
-- divide by y, change the sign, so y > x

Statement 1: z < x
From #2 above, we know that y > 0. Also we know that x < 0 and z < 0.
So,
|x-z| + |x| = x-z + (-x) = -z
Since z < 0, then -z > 0 and -z = |z| SUFFICIENT

Statement 2: y > 0
From #2 we know that z < x and same answer as statement 1.
Re: close
Guest



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guest11 wrote:
Guest83 wrote:
I may be way off here, let me know what you guys think.

Firstly, since both ZY and XY are both less than 0, this implies that Z and X are both negative or positive (depending on value of y)

if Y is negative:
Z and X are both positive. Since ZY < XY, this means X<Z.

if Y is positive:
Z and X are both negative. Since ZY < ZX, this means X>Z.


Now, statement 1 says that Z<X. This means that Y is positive.

|X-Z| + |X| = |Z| -> Z-X + X = Z -> YES


Statement 2:
Y < 0. This implies that X<Z.


|X-Z| + |X| = |Z| -> X-Z + X = Z -> NO


Therefore, both statements are sufficient.

Does this make sense?


Close.

From the question:
zy < xy < 0



Implies:
1. Since zy and xy are < 0 , then if y > 0, z < 0 and x < 0, and if y < 0, then x > 0 and z > 0.
2. If y > 0
-- divide by y, no change in sign, so z < x
3. If y < 0
-- divide by y, change the sign, so y > x

Statement 1: z < x
From #2 above, we know that y > 0. Also we know that x < 0 and z < 0.
So,
|x-z| + |x| = x-z + (-x) = -z
Since z < 0, then -z > 0 and -z = |z| SUFFICIENT

Statement 2: y > 0
From #2 we know that z < x and same answer as statement 1.


SORRY MADE A TYPO, RIGHT ANSWER BELOW:

Close.

From the question:
zy < xy < 0

Implies:
1. Since zy and xy are < 0 , then if y > 0, z < 0 and x < 0, and if y < 0, then x > 0 and z > 0.
2. If y > 0
-- divide by y, no change in sign, so z < x
3. If y < 0
-- divide by y, change the sign, so z > x (typo fixed)

Statement 1: z < x
From #2 above, we know that y > 0. Also we know that x < 0 and z < 0.
So,
|x-z| + |x| = x-z + (-x) = -z
Since z < 0, then -z > 0 and -z = |z| SUFFICIENT
Addendum: Take an example s.t. x,z<0 and and z<x. Say z=-10 and x=-5. Clearly -10<-5. Furthere more, x-z=-5-(-10)=-5+10=5. Since 5>0 we know that |x-z| = x-z.

Statement 2: y > 0
From #2 we know that z < x and same answer as statement 1.
Code:
Rey Fernandez
MGMAT STAFF

Joined: 06 Mar 2007
Posts: 389

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GMAT Prep Math zy < xy < 0 |x-z| + |x| = |z|
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