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Guest
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I get C.
xyz > 0 in two cases: 1. all the numbers are positive. 2. two of the numbers are negative and the other is positve. st 1: xy > 0 This statement is insufficient because x could be positive or negative to make it work. It does give a useful piece of information though: if x and y are both postive, xy > 0 and therefore z would have to also be positve to make xyz > 0. or if x and y are both negative, xy > 0 and therefore z would have to be positve to make xyz > 0. Basically, the statement is saying that z must be positive. st 2: xz > 0 This statement is insufficient because x could be positive or negative to make it work. It does give a useful piece of information though: if x and z are both postive, xz > 0 and therefore y would have to also be positve to make xyz > 0. or if x and z are both negative, xz > 0 and therefore y would have to be positve to make xyz > 0. Basically, the statement is saying that y must be positive. Combined From the two statements we know that z must be positive (st 1) and y must be postive (st 2). If y and z are both positive, the only way that xyz will be > 0 is if x is positive or x > 0. Therefore C. |
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Ron Purewal
MGMAT STAFF
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the easiest way to approach many problems involving the signs of numbers, like this one, is simply to enumerate all possibilities. in this problem, the question prompt requires xyz > 0; there are only four combinations of x, y, and z that satisfy that requirement:
(listed in order x y z) + + + + - - - + - - - + since the prompt condition must be satisfied, you can examine each given statement by choosing from this list, rather than slogging through lots of theory. (1) of the options on the above list, (+ + +) and (- - +) work here. x is positive in the former and negative in the latter, so this is insufficient. (2) of the options on the above list, (+ + +) and (- + -) work here. x is positive in the former and negative in the latter, so this is insufficient. (together) only (+ + +) works, so, sufficient. answer = c |
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brynat
Guest
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Perfect explanation. I am recommending Manhattan GMAT to all of my friends.
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Stacey Koprince
MGMAT STAFF
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Glad Rey helped and thanks for the rec!
Please remember to follow protocol: your subject line should be the first 5-8 words of the problem itself. Thanks! |
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