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Yep, same approach is good. First, let’s go through this one algebraically: Old pens = x, new pens = 1.05x. Old pencils = y, new pencils = .87y. New revenue = 99% of old revenue so (1.05x + .87y) = .99(x + y).
1.05x + .87y = .99x + .99y .06x = .12y 6x = 12y x = 2y
We sold twice as many pens as pencils. Now let’s try the number line approach: Place the pens at +5 on the number line, the pencils at -13, and the balance point at -1. Remember the distance from the balance point to an endpoint gets multiplied by the weight of that endpoint, and this number should be the same on both sides. 6 (5 minus -1) times the number of pens = 12 (-1 minus -13) times the number of pencils. Again, we see that we sold twice as many pens as pencils. This technique doesn’t work with all conceivable situations though (look up the problem about the election and the two parties for a good example), so you need to consider this technique carefully. And if you aren’t 100% sure you can use the number line method, don’t use it..
_________________ Tim Sanders Manhattan GMAT Instructor
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