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cube

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mrg_sort
 Post subject: cube
 Post Posted: Mon Aug 16, 2010 7:42 pm 
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a cube of volume of 72 .if it si divided into 8 equal cubes,the ratio of edge of smaller cube to orgininal cube is ??
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gokul_nair1984
 Post subject: Re: cube
 Post Posted: Tue Aug 17, 2010 2:45 am 
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Students


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Vol of original cube=72
Let 'a' be an edge..=>a^3=72

The cube is divided into 8 equal cubes
ie; the volume of the new cube =72/8=9
Therefore, a^3=9

Ratio =(9/72)^(1/3)...(Smaller Edge/Original Edge)

= cube root of (1/8)=1/2
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mschwrtz
 Post subject: Re: cube
 Post Posted: Fri Sep 03, 2010 2:48 am 
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ManhattanGMAT Staff


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Right. By the way, the original size of the cube is irrelevant. Each of the resulting small cubes is similar to the original cube. The volume:volume ratio of two similar solids is the cube of the line:line ration of the solids. In this case, the v:v ratio is 1/8, the cube of the e:e ratio of 1/2.
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