a.k.bhageria wrote:
Hi, I encountered this problem in my GMATPrep test-
Data sufficiency:
In the xy-plane does the line with equation y = 3x + 2 contain (r,s)
1. (3r + 2 - s)(4r + 9 - s) = 0
2. (4r - 6 - s)(3r + 2 - s) = 0
I answered - Both individually sufficient. The way i approached it was- replaced (r,s) in the required line eq. i.e. s = 3r + 2. If this equation is proved from the options then they're sufficient.
Now instead of solving each equation (which seemed like a lengthy process), I substituted s=3r+2 in each of the 2 options. Because I got 0 = 0, I concluded that this value of s is a solution for each of the two equations. Hence chose the answer.
Can you please tell me why this approach is wrong and how to solve it alternatively?
Thanks
Ankur
Hi,
(r,s) will lie on the line with equation y = 3x + 2, if in place of x and y respectively we put the coordinates of the point and the line equation is satisfied.
So , (r,s) will lie on y = 3x +2, if
s=3r+2 or in other words:
3r-s+2 = 0.
From St. 1:
(3r + 2 - s)(4r + 9 - s) = 0
i.e.
either
(3r + 2 - s) = 0 or (4r + 9 - s) = 0.
Say (3r + 2 - s) = 0 -->St. 1 satisfied and (r, s)
lies on given line.
Now say, (3r + 2 - s) not equal to zero, but
(4r + 9 - s) = 0
Then
St. 1 satisfied but (r, s)
does not lie on given line.
So St. 1 is not sufficient.Exactly same logic for St. 2.
St. 2 not sufficient.Combining both statements.
case 1: (3r + 2 - s)
is equal to zero
case 2: (3r + 2 - s)
is not equal to zero
let's discuss case (2):
This means that
(4r + 9 - s) = 0 and also (4r - 6 - s) = 0
which is absurd. (4r-s = -9 as well as 6--> not possible)
so only case 1 holds i.e.
(3r + 2 - s) is equal to zero
(C) is the answer.