jgeorge63 wrote:
The question stem mentions a 10 by 6 inch rectangular piece of paper used to construct the side of the cylinder. Keep in mind that there are two ways we can do this. With the 10 inch side as the height, imagine folding the piece of paper in a circular manner so that the two ends meet. The other way is to fold the paper with the 6 inch side as the height until the ends meet. Then the question becomes, what is the difference in the volume between the two?
Volume of a cylinder = Pi r^2 h. Here r is the radius and h is the height. Since we do not have the radius, we will need to calculate that somehow.
if you think about it, the length is the same thing as the circumference. You can see this visually when you fold the paper in the above described manner. Circumference is basically 2 Pi r. From this you can calculate r to be Circumference/(2 Pi)
Case 1: height = 10 and length (circumference) = 6 .
r = 6/(2 Pi) or 3/Pi
Vol = Pi (3/Pi)^2 * 10 = 90/Pi
Case 2: height = 6 and length (circumference) = 10
r = 10/(2 Pi) or 5/Pi
Vol = Pi (5/Pi)^2 * 6 = 150/Pi
Difference between the two (150/Pi) - (90/Pi) = 60/Pi
Answer b.
so r =
This explanation is good. Hope that makes sense.