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 Post subject: During a 40-mile trip, Marla traveled
 Post Posted: Mon Aug 03, 2009 5:39 pm 
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Posts: 7
During a 40-mile trip, Marla traveled at an average speed of x miles per hour for the first y miles of the trip and and at an average speed of 1.25x mph for the last 40-y miles of the trip. The time that Marla took to travel the 40 miles was what percent of the time it would have taken her if she has traveled at an average speed of x miles per hour for the entire trip?

1) x = 48
2) y = 20

Can you show how you would rephrase the question stem and what the RTD table would look like? I conceptually get why B (#2 is sufficient) but I dont think I know how to simply the question. The "what percent of time" is throwing me off.

Thanks!


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Wed Aug 05, 2009 11:55 pm 
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Students


Posts: 134
1) T= D/R

2) Question asks for T1/T2

3) Second statement says Y=20

4) Set up equation using Y=20:

(D1/R1)/(D2/R2)=

100 X [(20/R1) X (R2/20)]

5) Plug in Rates:

(20/X) X (1.25X/20)

6) At this point, realize that the "X"'s cross out, stop calculating and realize that B is sufficient.


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Tue Aug 18, 2009 10:46 pm 
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ManhattanGMAT Staff


Posts: 824
I like to draw a diagram when attacking these questions, so I can visualize what's going on. Then I try to break down the information given in the question, and what I'm looking for.

From the question, I see that there are two situations we are comparing:
(1) The time for traveling x mph for the first y miles and 1.25x mph for the last 40-y miles. We'll call this T1.
(2) The time for traveling x mph the entire 40 miles. We'll call this T2.

We want to find T1 / T2 * 100%

Let's rephrase T2 first. Time = Distance / Rate, so T2 = 40 miles / x mph = 40/x hours.

Now let's take a look at T1. Using an RTD Chart:
----------Rate * Time = Distance-----
1st Part x mph * ?? = y miles
2nd Part 1.25x mph * ?? = 40-y miles

The time for the first part is y/x hours, and the time for the second part is (40-y)/(1.25x) hours.

Now let's plug these values for T1 and T2 into the the formula.
T1 / T2 * 100%
= [(40-y)/(1.25x)] / (40/x) * 100%
= [(40-y)/(1.25x)][x / 40] * 100%
= [(100)(40-y)]/[(40)(1.25)]

Our rephrased question is "what is y?"

Clearly (2) alone is clearly sufficient, so (B) is the answer. Hope that helps.

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Ben Ku
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ManhattanGMAT


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Sat Oct 31, 2009 3:35 am 
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Posts: 32
Ben,

Don't you mean:

T1/T2 = [ y/x + (40-y/1.25x)] / (40/x) ?


Ben Ku wrote:
I like to draw a diagram when attacking these questions, so I can visualize what's going on. Then I try to break down the information given in the question, and what I'm looking for.

From the question, I see that there are two situations we are comparing:
(1) The time for traveling x mph for the first y miles and 1.25x mph for the last 40-y miles. We'll call this T1.
(2) The time for traveling x mph the entire 40 miles. We'll call this T2.

We want to find T1 / T2 * 100%

Let's rephrase T2 first. Time = Distance / Rate, so T2 = 40 miles / x mph = 40/x hours.

Now let's take a look at T1. Using an RTD Chart:
----------Rate * Time = Distance-----
1st Part x mph * ?? = y miles
2nd Part 1.25x mph * ?? = 40-y miles

The time for the first part is y/x hours, and the time for the second part is (40-y)/(1.25x) hours.

Now let's plug these values for T1 and T2 into the the formula.
T1 / T2 * 100%
= [(40-y)/(1.25x)] / (40/x) * 100%
= [(40-y)/(1.25x)][x / 40] * 100%
= [(100)(40-y)]/[(40)(1.25)]

Our rephrased question is "what is y?"

Clearly (2) alone is clearly sufficient, so (B) is the answer. Hope that helps.


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Thu Dec 03, 2009 4:08 am 
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ManhattanGMAT Staff


Posts: 824
victorgsiu wrote:
Ben,

Don't you mean:

T1/T2 = [ y/x + (40-y/1.25x)] / (40/x) ?


You're right! Thanks for the catch. Victor's correct expression can be simplified:

T1/T2 = [ y/x + (40-y/1.25x)] / (40/x)
= (y + (40-y)/1.25)/40
= (1.25y + 40 - y) / 50
= (0.25 y + 40)/50

In other words, the rephrasing is still "what is y?"

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Ben Ku
Instructor
ManhattanGMAT


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Fri Dec 04, 2009 11:02 pm 
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Students


Posts: 41
"what percent of the time it would have taken her if she has traveled at an average speed of x miles per hour for the entire trip? "

I had problems trying to understand, of what value is the question asking the percentage of !!
can someone pls break this statement me !

Thanks in advance !


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Thu Dec 24, 2009 7:27 pm 
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ManhattanGMAT Staff


Posts: 824
During a 40-mile trip, Marla traveled at an average speed of x miles per hour for the first y miles of the trip and and at an average speed of 1.25x mph for the last 40-y miles of the trip. The time that Marla took to travel the 40 miles was what percent of the time it would have taken her if she has traveled at an average speed of x miles per hour for the entire trip?

The actual time Marta spent, let's call that T1, is the combination of the first y miles at x mph and the second 40-y miles at 1.25x mph.

If she had traveled x mph the whole time, her new time T2 = 40/x.

The question is asking T1 is what percent of T2? In other words, T1 = (P/100)*T2.

Hope that makes sense.

_________________
Ben Ku
Instructor
ManhattanGMAT


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Sun Jul 24, 2011 9:08 am 
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Posts: 2
I'm having trouble seeing why the x's cancel out. Can you explain that part?


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Sun Jul 24, 2011 10:46 am 
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Course Students


Posts: 254
Hi NNadjmabadi1,

I am assuming that you are ok up to this part:
Ben Ku wrote:
T1/T2 = [ y/x + (40-y/1.25x)] / (40/x)


After this, you can take 1/x out common as a factor from both numerator and denominator. To better visualize this, I will use a new variable z, which is equal to 1/x. Also, I will treat numerator (T1) and denominator (T2) separately. Lets take the numerator and replace 1/x with z

T1 = yz + z(40-y)/1.25
= z [y + (40-y)/1.25]

Do the same with the denominator

T2 = 40z
= z(40)

Now you can see that z is common between Numerator and Denominator and can be cancelled out.

Regards

Sunil


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 Post subject: Re: During a 40-mile trip, Marla traveled
 Post Posted: Sat Jul 30, 2011 3:17 am 
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ManhattanGMAT Staff


Posts: 6765
yep


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