Manhattan GMAT Forums Forum Index

Reply to topic
The figure shows the top side of a circular medallion made
Guest
Guest


Reply with quote
Please refer to the attached problem.

I think I know how to start the problem, but not sure how to reach an answer that fits the answers provided by the exam.

Answer = Area of Circular Medallion - Area of Circular Colored Glass = Area of Metal Frame

pie*r^2 - pie *(r - s)^2

= pie * r^2 - pie * r^2 - 2s + s^2

Is that correct so far? And how do I reach a final answer?

Thank you!
Apologies - here is the attachment!
Guest
Guest


Reply with quote
givemeanid
Guest


Reply with quote
YOu are on the right track. You just need to factorize a little more.

pi*r^2 - pi*(r - s)^2
= pi * r^2 - pi * (r^2 - 2rs + s^2)
= pi*r^2 - pi*r^2 + 2pi*r*s - pi*s^2
= 2pi*r*s - pi*s^2
= pi*s(2r - s)
= E
Thanks!
Guest
Guest


Reply with quote
so close....clear explanation.

Thanks givemeanid.
Stacey Koprince
MGMAT STAFF

Joined: 06 Mar 2007
Posts: 2590
Location: San Francisco
Reply with quote
Nice job once again, givemeanid. You've been a great help on the forums - keep up the good work!
The figure shows the top side of a circular medallion made
All times are GMT - 5 Hours  
Page 1 of 1  

  
  
 Reply to topic