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| OG - PS - #88 |
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givemeanid
Guest
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RGWBY is the bead pattern and it repeats. So, the 3rd, 8th, 13th, 18th... beads will be W.
(This is similar to an AP series). So, number of beads - 3 has to be divisible by 5 for it to be a White bead. 68 - 3 = 65 = 5*13. Answer is E. |
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Dan Bernstein
MGMAT STAFF
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givemeanid, thanks for the explanation!
-dan |
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greenpepper
Guest
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Thank you, givemeanid.
greenpepper |
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| further explaination? |
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shaftbmf
Guest
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i recognize that this is a combinatorics problem but it is still unclear. Can i get a fuller explanation on the approach? I don't understand how you get 68? :?
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Stacey Koprince
MGMAT STAFF
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It's actually a sequences question - you want to use the pattern to get to the answer.
The pattern is RGWBY RGWBY RGWBY etc (keeps repeating) So, for example, the red beads are #1, #(1+5), #(1+5+5), etc, or 1, 6, 11, etc. The green beads are #2, #(2+5), #(2+5+5), etc, or 2, 6, 12, etc and so on for the other colors We want to find what N could be, and N represents the last bead. We're told the last bead is white, so what are the options for white? #3, #(3+5), #(3+5+5), etc, or 3, 8, 13, etc. I can figure out what works from my answer choices in two different ways. The easiest way (unique to this problem set-up): each time, I'm adding 5. So, for N, it could be 3, 8, 13, 18, 23, 28... noticing a pattern? It always ends with either 3 or 8. The only answer choice that ends with either 3 or 8 is E. The common way (can use on any problem of this type) is to set it up algebraically. For white, I start with 3 and then each time I add 5 more. That can be expressed as 3 + 5x. The first white bead is just at 3, the second white bead is at 3 + 5(1) = 8, the third white bead is at 3 + 5(2) = 13, and so on. This means the answer will be 3 + some multiple of 5. Subtract 3 from every answer choice. The right answer should be a multiple of 5 (because we've removed the first 3). Only E fits this requirement. |
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| OG - PS - #88 |
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