If xy+z=x(y+z) wich must be true?

1-X=0,Z=0
2-X=1,Y=1
3-Y=1,Z=0
4-X=1,Y=0
5-X=1,Z=0

Correct answer is E) X=1 and Z=0 which leaves y+0=y+0
I fortunately did it right in the GMATPrep and it was question number 2 but It should be much easier or do I need a rest right now because I cannot see anything?

1- If X=0,Z=0 this yield--> 0*y+0=0*y+0*0--> 0=0
2- If X=1,Y=1 this yield--> 1*1+z=1*1+1*z--> 1+z=1+z
3- If Y=1,Z=0 this yield--> x*1+0=x*1+x*0--> x=x
4- If X=1,Y=0 this yield--> 1*0+z=1*0+1*z--> z=z
5- If X=1,Z=0 this yield--> 1*y+0=1*y+1*0--> y=y

Obviously I´m missing something, it couldn´t be so difficult. I´m quite tired after working, so maibe tomorrow I´ll see it clear. Why is 5 right and not the rest?

Thanks

Luci

Thanks

There is an easy approach to solve the problem, here it goes: -

We know from the question xy + z = x(y+z)

xy + z = xy + xz

z = xz
or z-xz = 0
or z(1-x) = 0

If you look above, the solution of the above equation is 1-x =0 or z=0

So the answer is (A)

Hope it helps

GMAT 2007

Thanks GMAT 2007, it helps and you are right with your explantion and your answer, but I still dont know why the other solutions seems to make sens as well...

If we work in the question we get the correct result as GMAT 2007 did, but if we simply substitute values all of them seems to by a possible solution.

Any explanation?

Thanks