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| A certain city with a population of 132000, is divided into |
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GMAT 2007
Guest
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Total population = 132000 & no. of districts = 11.
If divided equally, the population of each district = 132000/11 = 12000 The condition to satisfy = no district can have the population > 10% of any other district. For ex - assume district (A) has the least population, now the only way to get the min. population of (A) so that no other district can have population > 10% of (A) is to reduce the population of (A) to minimum and add the reduced amount equally into the rest 10 districts. If you look at the answer choices the least possible population of (A) when no other district will have pop > 10% of A would be (11000) If A = 11000 the reduced pop = 1000. so 1000 can be increased in rest of 10 districts, so the population of rest of the 10 district= 12100 10 % of (A's population) = 10% of 11000 = 1100. So rest of the districts have exactly 10% more population than (A) Hence the answer is (D) Hope it helps. GMAT 2007 |
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Harish Dorai
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Great explanation.
Question for MGMAT - What would be the difficulty level of questions like this? I guess this is a 700+ level question. |
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