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MBA Applicant 2007/8
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Post subject: OG - QUANT REVIEW PS - #114  Posted: Sun Jul 22, 2007 1:28 pm |
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Is 1/(a-b) < b - a?
1) a < b
2) 1 < |a-b|
Step 1: Rephrase the question:
Is (a - b)^2 < -1?
Step 2
Using,
AD
BCE
Step 3:
(1) - a -b <0 ---> (a - b)^2 is always positive and therefore the answer is NO--- SUFF
(2) if a -b >0 , then a -b >1----> which also means (a-b)^2 >0 and hence NOT less than -1--- NO
if a-b <0, a - b < -1 ------> which means that (a-b)^2 >0 and hence NOT less than -1 --- NO ===SUFF
But the answer is incorrect. Can u please point out the flaw in my reasoning and suggest an improved approach? I didnt like the explanation in OG.
Thank you in advance
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givemeanid
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Post subject: Posted: Mon Jul 23, 2007 10:32 am |
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Is 1/(a-b) < (b-a)?
1) a < b
a-b < 0
1/(a-b) < 0
b-a > 0
Sufficient.
2) 1 < |a-b|
|a-b| < 1
-1 < a-b < 1
-1 < b-a < 1
So, one can be +ve and the other -ve. Cannot tell which one is which.
NOT sufficient.
Answer is A. What is OA?
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givemeanid
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Post subject: Posted: Mon Jul 23, 2007 10:38 am |
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Typo in the previous post. If this post also has a typo, please beat me back to senses.
Is 1/(a-b) < (b-a)?
1) a < b
a-b < 0
1/(a-b) < 0
b-a > 0
Sufficient.
2) 1 < |a-b|
|a-b| > 1
a-b < -1 or a-b > 1
b-a > 1 or b-a < -1
When a-b < -1, b-a > 1.
When a-b > 1, b-a < -1.
Both of those are sufficient.
Answer is D.
What is OA?
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givemeanid
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Post subject: Posted: Mon Jul 23, 2007 11:07 am |
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You know, trying to solve DS at work is a BAD idea. BAD BAD idea.
When a-b < -1, b-a > 1. True.
When a-b > 1, b-a < -1. False.
Insufficient.
Answer should be A. I am done. This is it. Rome is burning, my friends.
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StaceyKoprince
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Post subject: Posted: Mon Jul 23, 2007 10:46 pm |
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| ManhattanGMAT Staff |
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Posts: 6077
Location: San Francisco
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We've all had days like that, givemeanid. :)
You've hit on the issue, though - when multiplying or dividing an inequality by a negative, we have to switch the sign. We're not told whether the quantity (a-b) is pos or neg, so we have to check this both ways.
IF a-b is pos, then 1 < (a-b)(b-a) (and you can simplify further from there)
IF a-b is neg, then 1 > (a-b)(b-a) (and again you can simplify further from here)
But the point is that I have to follow both possibilities through and any particular statement is only sufficient if BOTH equations give me the SAME definitive answer, yes or no.
I'll stop there - try this again and come back if you have more questions.
_________________
Stacey Koprince
Instructor
Director of Online Community
ManhattanGMAT
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Guest
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Post subject: Different approach Posted: Tue Jul 24, 2007 12:51 pm |
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Is 1/(a-b) < b - a?
Rephrase: 1< (a-b) (b-a)
1) a < b
If a, b are both +ve, Both -ve, or -ve & +ve
1 > (a-b) (b-a)
Statement (1) is sufficient.
2) 1 < |a-b|
This statement mentions |a-b| and nothing about (b-a)
(b-a) can be +ve or -ve.
Therefore, statement (2) is not sufficient.
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