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| If n is a multiple of 5 and n = p^2(q),... |
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mbandai
Guest
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hey pash 19,
I think there are a couple of ways to tackle this problem. The easiest way, I think, would be to just remember that p^2(q) is a multiple of 5, and then move on to the answer choices. a) p^2. This could very well be 3^2. So long as q is 5, then p^2(q) will be a multiple of 5. But p^2, when p=3, is NOT a multiple of 25. Eliminate b) q^2. Same reasoning as above. q^2 can also be 3^2. If p=5, then p^2(q) will be a multiple of 5. But q^2, in this case is 3^2, and NOT a multiple of 25. Eliminate. c) p^2(q^2). In this case, remember that the original p^2(q) is a multiple of 5, meaning either p or q is 5. That means that either p^2 or q^2 will be 5^2, or 25. This makes p^2(q^2) a multiple of 25. AHA! d) p^2(q). Basic idea is the same as a) and b). p^2 can be 3^2 and q=5. 3^2(5) = 45 and that is NOT a multiple of 25. Eliminate. I think there must have been a choice e), but the reasoning should be the same as the wrong choices. Hope this helps. |
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| Thanks! |
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pash19
Guest
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Thank you for the great explanation! :D
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mbandai
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you're welcome! :D
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Ron Purewal
MGMAT STAFF
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| If n is a multiple of 5 and n = p^2(q),... |
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