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| Yes/No DS questions - picking numbers for multiple variables |
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Ron Purewal
MGMAT STAFF
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well, the first thing you should do is look for SUBSTITUTIONS or COMBINATIONS OF VARIABLES. if you look for those, then the resultant simplifications will greatly ease the amount of plugging/guessing required of you - or, if the transformation cancels out enough quantities, eliminate that plugging/guessing altogether.
for instance, take statement (2) here. notice that there's the combination (x - y) in both statement (2) and the question prompt. therefore, solve for this combination in both parts: x - y < z (from the problem statement) x - y > 1 (from statement 2) since (x - y) is less than z but more than 1, it follows that z is greater than 1; this is sufficient. you should ONLY look to plug in numbers if these sorts of manipulations fail; it's unlikely that a problem geared toward plugging in numbers would require the plugging in of LARGE quantities of numbers. |
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Guest
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How do we deal with the first inequality?
z<x-y-1 |
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Ron Purewal
MGMAT STAFF
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it appears that that statement hasn't been transcribed correctly; see the result below. maybe the inequality sign was transcribed incorrectly, or ... ? -- here's a useful general rule. GENERAL RULE: YOU CAN ADD TWO INEQUALITIES IF THE INEQUALITY SIGNS FACE IN THE SAME DIRECTION. the problem statement says that x - y - z < 0. since this one is also "less than", you can add them, giving (x - y - z) + z < 0 + (x - y - 1) x - y < x - y - 1 0 < -1 this is a contradiction, indicating that either the problem statement or statement 1 (or possibly both, but at least one of them) has been transcribed incorrectly. whoops |
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| Yes/No DS questions - picking numbers for multiple variables |
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