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| gmat prep toughmixture problem, please help |
| solution |
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babu
Guest
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(.01x + .02y+.03z)/(x+y+z)=.015
=>x=y+3z |
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bharri7
Guest
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What is the official answer?
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Guest
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The answer is A (x=y+3z) |
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Ron Purewal
MGMAT STAFF
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mixture problems work in the same way as RTD problems; the equation, in this case, is (% fat) x (total gallons) = (gallons of fat). the % works like a rate, the total gallons like a time, and the gallons of fat like a distance.
set up a chart, in which the rows are (% fat), (total gallons), and (gallons of fat). first row: 0.01, x, 0.01x second row: 0.02, y, 0.02y third row: 0.03, z, 0.03z TOTALS row: 0.015, (x + y + z), (0.01x + 0.02y + 0.03z) -- notice that both of the "gallons" columns add, but the percentages DON'T add. therefore, 0.015(x + y + z) = 0.01x + 0.02y + 0.03z the rest of the problem is as posted above. -- you can also pick numbers; i can show detail of this method if you like. -- gallons of fat! yummy! |
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| gmat prep toughmixture problem, please help |
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