guys,

could you pls help me on th question attached

Imagine the Center C on the OR diameter.

Now Angle PCO=2*35=70.
Thus minor arc PO=(70/360)*2*pi*9=(7/2)*pi

Now Angle QCR=70.
Thus minor arc QR= (7/2)*pi

Hence, minor arc PQ = 9*pi - (7/2)*pi - (7/2)*pi = 2*pi

Maverick, you are correct.

when I was solving this question, I tried to find length of 'chord' instead of the 'arc'.

this works.

if you don't like doing so much math with pi and fractions, you can always find the number of degrees in arc pq first. since angles qpr and pro are both 35 degrees (alternate interior angles), arcs op and qr must both be 70°. therefore, the degree measure of arc pq is 180 - 70 - 70 = 40°.

you can then find the length directly as (40/360)(18pi) = 18pi/9 = 2pi.

not that much more efficient than the solution posted here, but any degree (heh, "degree") of extra efficiency is worth it for the extra time gained.[/list]

thanks friends..