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Triangle-Gmat prep

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Capthan
 Post subject: Triangle-Gmat prep
 Post Posted: Thu Jun 12, 2008 3:22 pm 
For any triangle in the xy-coordinate plane, the center of T is defined to be the point whose x-coordinate in the average(mean) of the x-coordinate of the vertices of T and whose y-coordinate in the average of the y-coordinate of the vertices of T. If a certain triangle has vertices at the points(0,0) and (6,0) and center at point(3,2) what are the coordinates of the remaining vertex?
3, 4
3, 6
4, 9
6, 4
9, 6

please explain the answer. Thanks
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LoveGmat
 Post subject: easy
 Post Posted: Fri Jun 13, 2008 2:53 am 
obviously according to the question:

3=(6+0+x)/3
2=(0+0+y)/3 so X= 3 Y=6
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rfernandez
 Post subject:
 Post Posted: Fri Jun 13, 2008 4:29 am 
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Course Students


Posts: 386
Perhaps not so obvious to all, but a good solution nonetheless. Well done.
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