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| A manufacturer produced x percent more video cameras in 1994 |
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GMAT 2007
Guest
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Luci - this one is tricky, and it lies in the question stem itself.
No. of Video Cameras produced in 1993 = 1000 Assume 'a' be the increase in no. of video cameras in 1994, So x = (a/1000)*100 or a = 10x Similarly assume b be the increase in no. of video cameras in 1995, So y = (b/(1000+10x))*100 or b = ((100+x)/10)*y Now total no. of video cameras in 1995 = 1000 + a + b = 1000 + 10x + ((100+x)/10)*y...(1) Solving (1) 10(100+x) + ((100+x)/10)*y = (100+x)(10+y/10) = (100+x)(100+y)/10 = 10000+10(x+y) + xy/10 = 10(1000+(x+y)+xy/100) Now statement (2) gives us the value of the expression (x+y)+xy/100. Hence it is sufficient. GMAT 2007 |
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Luci
Guest
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Amazing explanation GMAT 2007. Thanks a lot. Although I think it is a very tough problem, I dont think I will be able to solve it in 2 minutes. Not because the logic of the question stem, which is brilliant how you did it, but all the factoring you have done seems too tough to me. This is one of those to try a good guess and keep going I think, :-).
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Guest
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We could also do this problem the following way:
1993 = 1000 video cameras 1994 = 1000*(1+x/100) 1995 = 1000*(1+x/100)(1+y/100) group the equation for 1995 1995 = 1000*(1+x/100+y/100+xy/10,000) Evaluate the statements Statement 1) This is insufficient because we need the values for x and y Statement 2) is the further simplified from the equation we have x+y+xy/100=9.2, which can be simplified to fit our rephrased equation 1995 = 1000*(1+x/100+y/100+xy/10,000) = 9.2 1+x/100+y/100+xy/10,000=.0092 (divide both sides by 1000) x/100+y/100+xy/10,000=.0092-1=.9908 (subtract 1 from both sides but ignore the negative sign because you cannot sell negative video cameras) x+y+xy/100=99.08 (after multiply throughout by 100) |
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Ron Purewal
MGMAT STAFF
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well played. |
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| A manufacturer produced x percent more video cameras in 1994 |
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