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| Tricky Sequence and series question |
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dhoomketu
Guest
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We can write any of the elements of the series in the form of either:
a(x)=45+7(X) such as for a1, a3, a5 etc. or as; a(x)=49+7(X) such as for a2, a4 etc; here x goes from 0 to n Now the thing is any number of the series from either 45 or 49 is subtracted should be divisible by 7. Let us look at each choice: Ø 323--------Both (323-45) and (323-49) aren't divisible by 7 Ø 463--------Both not divisible by 7 Ø 498--------Both not divisible by 7 Ø 533--------Both not divisible by 7 Ø 598--------(598-45) is divisible by 7 so this could be the answer Am I correct? |
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Guest
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Absolutely, my friend...u r answer is correct and thanks for the fantastic explanation. Would appreciate if u can post answers to the other remainder theory question that i had posted. |
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AG
Guest
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The number in the series are of the following form
even numbers - div by 7 odd numbers - when divided by 7 remainder is 3 only E follows this patern. |
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Rey Fernandez
MGMAT STAFF
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Very good solution. Nice work.
In the future, per this forum's guidelines, please do not post questions unless you know their sources. Thank you for your understanding. Rey |
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| Tricky Sequence and series question |
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