Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of these animals are cows?
(1) The farm has more than twice as mnay cows as it has pigs.
(2) The farm has more than 12 pigs

Answer=C

Thanks!

Rephrase the question:
60 * 2/3 = 40 pigs or cows
p + c = 40

1)
Example 1: pigs = 2 cows = 38
Example 2: pigs = 4 cows = 36
Insufficient

2)
Example 1: pigs = 13 cows = 27
Example 2: pigs = 39 cows = 1
Insufficient

Together)
pigs = 13 cows = more than twice 13, or 26
13 + c = 40
c = 27
Valid, since 27 is greater than 26

pigs = 14 cows = more than twice 14, or 28
14 + c = 40
c = 26
Invalid, since 26 is not more than 28

Any larger number of pigs will also be invalid.

Sufficient. There are 13 pigs and 27 cows.

nice!

But doesn't statement 1 mean: cows = 2(pigs). We have two equations...couldn't we solve for cows?

Doh...It's because it says MORE than twice right?

Yep. We'd just know a range based on that and the question asks us for one specific number.