|
Hi,
You need to try to simplify the equation. First let's work on the left hand side since it looks 'more complicated': Since (n*a + n*b + n*c + n*d) = n * (a + b + c + d) we can start with 2^x + 2^x + 2^x + 2^x = 2^x * ( 1 + 1 + 1 + 1) = 2^x * 4 That is, n is equal to 1 and a, b, c, and d, are all equal to 2^x.
Since 4 = 2^2, we can write this as 2^x * 4 = 2^x * 2^2
Since a^b * a^c = a^(b+c) we can finally write 2^x * 2^2 = 2^(x+2)
So what we have now, substituting that last expression into the original left hand side of the equation, is 2^(x+2) = 2^n
The next rule to be used says that if a is neither -1, 0, nor 1 and if a^u = a^v then u=v. Thus x+2 = n.
|