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Percentile problem

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anoo.anand
 Post subject: Percentile problem
 Post Posted: Sun Oct 11, 2009 2:25 am 
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Students


Posts: 73
Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class there were 19 grades higher than Angela’s. If nobody had Angela’s grade, then Angela was what percentile of the two classes combined?
a. 72
b. 80
c. 81
d. 85
e. 92


Tried searching ...has not yet been solved.. :)

I solved it doiing:

number of students less then angela = 71 ..in class 1

no of students less then angela = 80-19 = 61 -60 = 60 below her in class 2

thus : 71 + 60 = 131

( x/100)*160 = 131

=> x = (131 * 100 ) / 160 = 81 .87 .. = 81

but the answer is not 81 . :)
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acethegmat
 Post subject: Re: Percentile problem
 Post Posted: Fri Oct 23, 2009 4:07 pm 
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Students


Posts: 32
Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class of 100 students there were 19 grades higher than Angela’s. If nobody had Angela’s grade, then Angela was what percentile of the two classes combined?

Your question stem missed out some key words. You should be able to solve it now:

90th percentile means 8 of 80 students
19 of 100 students - given

hence 19+8 = 27 students

27/180 - 15%
1 - 15% = 85%

Is 85 % the answer..?
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RonPurewal
 Post subject: Re: Percentile problem
 Post Posted: Sat Oct 24, 2009 8:31 am 
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ManhattanGMAT Staff


Posts: 7146
post4998.html#p4998

so is it angela, or amy?
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nitin_prakash_khanna
 Post subject: Re: Percentile problem
 Post Posted: Sat Oct 24, 2009 10:57 am 
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Students


Posts: 68
It looks like Amy got those grades in 2007 and Angela got the same in 2009 :>
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Ben Ku
 Post subject: Re: Percentile problem
 Post Posted: Thu Oct 29, 2009 1:18 am 
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ManhattanGMAT Staff


Posts: 823
Haha. Nice.

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Ben Ku
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ManhattanGMAT
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