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unique
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Posted: Tue Aug 21, 2007 5:14 pm |
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if x is not equal to -y
is x-y/x+y > 1
1. x>0
2. y<0
How to solve this w/o picking nos.
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Stacey Koprince
MGMAT STAFF
| Joined: 06 Mar 2007 |
| Posts: 2130 |
Location: San Francisco
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Posted: Tue Aug 21, 2007 6:21 pm |
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Without picking numbers? Why would you want to not do that? :)
Given: x is not equal to -y.
Is (x-y)/(x+y) > 1? (I'm going to assume this is how it's supposed to be written, not (x) - (y/x) + (y) > 1, because otherwise why would they tell me x is not equal to -y? Correct me if I'm wrong.)
I can see from my statements that this is going to revolve around whether these guys are positive or negative. So I'll keep that in mind and use logic.
(1) x is positive. Nothing about y, so it could be positive or negative.
- if y is positive, then (x-y) could be positive or negative and (x+y) has to be positive. So the quotient could be -/+ or +/+, so I can't tell if it will be greater than 1. I can stop here - this statement is now insufficient...
- ...but I'll show the other option anyway. If y is negative, then (x-y) must be positive and (x+y) could be positive or negative. Same logic as above, can't tell.
(2) y is negative. Nothing about x, so it could be positive or negative.
- if x is positive, then (x-y) must be positive and (x+y) could be positive or negative. So the quotient could be +/- or +/+, so I can't tell if it will be greater than 1. I can stop here - this statement is now insufficient...
- ...but I'll show the other option anyway. If x is negative, then (x-y) could be positive or negative and (x+y) must be negative. Same logic as above, can't tell.
(1) AND (2). x is positive, y is negative. If this is true, then (x-y) must be positive and (x+y) could be positive or negative. I still can't tell! Argh. E.
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