Register    Login    Search    Rss Feeds

 Page 1 of 1 [ 8 posts ] 



 
Author Message
 Post subject: NP Guide (3rd Ed) - Divisibility & Primes p.106
 Post Posted: Sun Aug 09, 2009 10:58 pm 
Offline
Course Students


Posts: 2
I have a question regarding In Action Problem #25 on p.106 of the number properties (3rd Edition).

If x,y, and z are integers, is x even?
1) 10^x = (4^y)*(5^z)

--> I got (2^x)*(5^x) = (2^2y)*(5^z)
from this, I can infer that 2^x = 2^2y and 5^x = 5^z since 2 and 5 are primes.

Thus --> x=2y which i know x is for sure even;
BUT: -->x = z which i DO NOT know anything about z.

Therefore I think A is insufficient because x can be both even (2y) or odd (since z can be odd or even). However, the answer is that A is sufficient.

Please explain why A is sufficient.

Thanks.


Top 
 Post subject: Re: NP Guide (3rd Ed) - Divisibility & Primes p.106
 Post Posted: Tue Aug 18, 2009 12:31 pm 
Offline
ManhattanGMAT Staff


Posts: 823
Quote:
If x,y, and z are integers, is x even?
1) 10^x = (4^y)*(5^z)

--> I got (2^x)*(5^x) = (2^2y)*(5^z)
from this, I can infer that 2^x = 2^2y and 5^x = 5^z since 2 and 5 are primes.

Thus --> x=2y which i know x is for sure even;
BUT: -->x = z which i DO NOT know anything about z.

Therefore I think A is insufficient because x can be both even (2y) or odd (since z can be odd or even). However, the answer is that A is sufficient.


I think that x = 2y (x is even) and x = z (z is an integer) do NOT contradict each other. Basically x must fit BOTH conclusions, so x must be even.

_________________
Ben Ku
Instructor
ManhattanGMAT


Top 
 Post subject: Re: NP Guide (3rd Ed) - Divisibility & Primes p.106
 Post Posted: Tue Aug 18, 2009 7:04 pm 
Offline
Course Students


Posts: 2
Thank you for your response. I agree with your explanation.


Top 
 Post subject: Re: NP Guide (3rd Ed) - Divisibility & Primes p.106
 Post Posted: Wed Aug 19, 2009 12:07 pm 
Offline
ManhattanGMAT Staff


Posts: 823
Glad it helped!

_________________
Ben Ku
Instructor
ManhattanGMAT


Top 
 Post subject: Re: NP Guide (3rd Ed) - Divisibility & Primes p.106
 Post Posted: Tue Dec 01, 2009 3:12 am 
Offline
Students


Posts: 23
I have a question though I disagree with the solution.

Statement A by itself is NOT SUFFICIENT, x could = 0, which is not odd.

You need statement 1 and 2 to be sufficient , as statement 2 guarantees x != -


Top 
 Post subject: Re: NP Guide (3rd Ed) - Divisibility & Primes p.106
 Post Posted: Thu Dec 03, 2009 2:16 am 
Offline
ManhattanGMAT Staff


Posts: 823
ankitp wrote:
I have a question though I disagree with the solution.

Statement A by itself is NOT SUFFICIENT, x could = 0, which is not odd.

You need statement 1 and 2 to be sufficient , as statement 2 guarantees x != -


Can you expand on your thoughts? I don't really understand your question. The problem asks whether x is even. As we worked out above, we figured out that in statement (1), x must be even. You're right, x could be 0; this fits what we said about statement (1) and does not present a counterexample.

_________________
Ben Ku
Instructor
ManhattanGMAT


Top 
 Post subject: Re: NP Guide (3rd Ed) - Divisibility & Primes p.106
 Post Posted: Fri May 13, 2011 2:41 pm 
Offline
Students


Posts: 10
Hi ,
Reviving a very old thread..
Was just going through this problem on NPG 4 Ed.
Fairly easy one ; but the nly doubt I have is '
Do we have to assume in exponential questions that the integers are +ve? Bcoz the question stem says "If x, y, and z are integers, is x even?" cant X, Y , Z be negative?

Thanks
Sudhir


Top 
 Post subject: Re: NP Guide (3rd Ed) - Divisibility & Primes p.106
 Post Posted: Sat May 14, 2011 10:33 pm 
Offline
ManhattanGMAT Staff


Posts: 1857
sudhir.18n wrote:
Hi ,
Reviving a very old thread..
Was just going through this problem on NPG 4 Ed.
Fairly easy one ; but the nly doubt I have is '
Do we have to assume in exponential questions that the integers are +ve? Bcoz the question stem says "If x, y, and z are integers, is x even?" cant X, Y , Z be negative?

Thanks
Sudhir


x, y, and z could possibly be negative, but the issue is whether x is even. We know that x=2y, so even if y=-1 and x=-2, x would still be even. Negative numbers can absolutely be distinguished as even and odd.

_________________
Jamie Nelson
ManhattanGMAT Instructor


Top 
Display posts from previous:  Sort by  
 
 Page 1 of 1 [ 8 posts ] 





Who is online

Users browsing this forum: No registered users and 0 guests

 
 

 
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
Jump to: