Register    Login    Search    Rss Feeds

 Page 1 of 1 [ 5 posts ] 



 
Author Message
 Post subject: Modulus question
 Post Posted: Fri Dec 09, 2011 7:26 am 
Offline
Students


Posts: 2
If mod x + 4 = 2 then x = ?

1) x^2 not equal to 4
2) x^2 = 36

I have tried solving the question and pretty much through it. I am not sure why option 2 is sufficient along with option 1.

Below is my solution

Case 1 -
|x + 4| = x + 4 = 2 makes x = -2. On back-check answer is consistent with the initial assumption that x + 4 is positive.

When x = -2, x + 4 = 2, which is indeed positive. This means that x = -2 is a good answer.

Case 2 -
x + 4 is negative makes |x + 4| = -x - 4 = 2. This means that -x = 6 or x = -6. Again we back-check: -6 + 4 = -2, which is negative.

So there are two answers to this problem: x = -2 or x = -6.

Now, getting to our stmts:

1. means that x is neither 2 or -2. This eliminates x = -2 and leaves x = -6. So 1 is sufficient.

2. x^2 = 36 makes x as 6 or -6. QUERY - At this point, we are sure that x = -6 corresponds to the main equation answer but how does it eliminate x=-2? It actually gives no infor if x =-2 should be discarded. Should I assume the overlapping value of -6 should be taken in this case? Please advice.


Top 
 Post subject: Re: Modulus question
 Post Posted: Sat Dec 10, 2011 3:54 pm 
Offline
Students


Posts: 21
With the info in the problem statement and option 2, we have two equations

|x+4| = 2 with a solution set of x = {-6, -2}; and
x^2 = 36 with a solution set of x = {-6, +6}

the fundamental rule of solving equations is that the final solution should satisfy both the equations and only -6 does that.

As to your question of why we should disregard - 2, by that logic why didn't you question the reason for disregarding +6 in the second case.

Remember that just because the first equation is mentioned in the problem statement doesn't give it any precedence over the second, both of them have equal standing and hence the acceptable solution is only that value which satisfy both the equations.



jaspreetp wrote:
If mod x + 4 = 2 then x = ?

1) x^2 not equal to 4
2) x^2 = 36

I have tried solving the question and pretty much through it. I am not sure why option 2 is sufficient along with option 1.

Below is my solution

Case 1 -
|x + 4| = x + 4 = 2 makes x = -2. On back-check answer is consistent with the initial assumption that x + 4 is positive.

When x = -2, x + 4 = 2, which is indeed positive. This means that x = -2 is a good answer.

Case 2 -
x + 4 is negative makes |x + 4| = -x - 4 = 2. This means that -x = 6 or x = -6. Again we back-check: -6 + 4 = -2, which is negative.

So there are two answers to this problem: x = -2 or x = -6.

Now, getting to our stmts:

1. means that x is neither 2 or -2. This eliminates x = -2 and leaves x = -6. So 1 is sufficient.

2. x^2 = 36 makes x as 6 or -6. QUERY - At this point, we are sure that x = -6 corresponds to the main equation answer but how does it eliminate x=-2? It actually gives no infor if x =-2 should be discarded. Should I assume the overlapping value of -6 should be taken in this case? Please advice.


Top 
 Post subject: Re: Modulus question
 Post Posted: Sun Dec 25, 2011 11:49 pm 
Offline
ManhattanGMAT Staff


Posts: 1857
Nice response, thanks!

_________________
Jamie Nelson
ManhattanGMAT Instructor


Top 
 Post subject: Re: Modulus question
 Post Posted: Tue Jan 03, 2012 1:50 pm 
Offline
Course Students


Posts: 15
nice explanation!


Top 
 Post subject: Re: Modulus question
 Post Posted: Tue Jan 10, 2012 7:29 pm 
Offline
ManhattanGMAT Staff


Posts: 2242
Location: Southwest Airlines, seat 21C
yay

_________________
Tim Sanders
Manhattan GMAT Instructor


Top 
Display posts from previous:  Sort by  
 
 Page 1 of 1 [ 5 posts ] 





Who is online

Users browsing this forum: No registered users and 1 guest

 
 

 
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
Jump to: