Register    Login    Search    Rss Feeds

 Page 1 of 1 [ 5 posts ] 



 
Author Message
 Post subject: MGMAT Tought Question Bank Problem - Equations, Inequalities
 Post Posted: Wed Jun 22, 2011 10:06 pm 
Offline
Course Students


Posts: 5
Is |x| < 1 ?

(1) |x + 1| = 2|x – 1|

(2) |x – 3| > 0

My approach for this is

I was able to rephrase the stmt to -1 < x < 1, and realize that stmt (2) was insufficient as it yields x>3 x<3....

BUT I have no idea how to handle Stmt (2), and to be honest I didn't really understand the explanation provided in the question bank. Can someone please explain to me how to approach Stmt(1)?

My exam is next Friday, so would appreciate a response in the next few days.
Thanks


Top 
 Post subject: Re: MGMAT Tought Question Bank Problem - Equations, Inequalities
 Post Posted: Sat Jun 25, 2011 4:56 am 
Offline
Students


Posts: 1
My take on this is:

Statement 1: |x+1| = 2|x-1|

Can be broken down into two cases:

a. x + 1 = 2(x-1)
b. x + 1 = -2(x-1)

solving a:
x + 1= 2x - 2
-x = -3
x = 3

solving b:
x + 1 = -2x +2
3x =1
x = 1/3

|X|=|3|<1..No
|1/3|<1.. Yes

1. Not sufficient

2. |X-3|>0
x - 3 >0 or x-3<0
Again |X|<1 can be yes or no while testing different values.
Not sufficient.

Combining 1 and 2

We get |X|=1/3 <1 Yes. So Ans is "C"..


Top 
 Post subject: Re: MGMAT Tought Question Bank Problem - Equations, Inequalities
 Post Posted: Sat Jul 02, 2011 12:18 pm 
Offline
ManhattanGMAT Staff


Posts: 1857
Nice work arora!

_________________
Jamie Nelson
ManhattanGMAT Instructor


Top 
 Post subject: Re: MGMAT Tought Question Bank Problem - Equations, Inequalities
 Post Posted: Wed Jul 20, 2011 3:09 am 
Offline
Students


Posts: 2
arora.sumit88 wrote:
My take on this is:

Statement 1: |x+1| = 2|x-1|

Can be broken down into two cases:

a. x + 1 = 2(x-1)
b. x + 1 = -2(x-1)

solving a:
x + 1= 2x - 2
-x = -3
x = 3

solving b:
x + 1 = -2x +2
3x =1
x = 1/3

|X|=|3|<1..No
|1/3|<1.. Yes

1. Not sufficient

2. |X-3|>0
x - 3 >0 or x-3<0
Again |X|<1 can be yes or no while testing different values.
Not sufficient.

Combining 1 and 2

We get |X|=1/3 <1 Yes. So Ans is "C"..


Hello,
For statement 1 , i got X = 1/3 or X = 3 ==> not sufficient
For Statement 2, i got X < 3 or X > 3 , Can you provide number examples here?
For X>3, i take 4 , hence |4| < 1 , NO
For X<3 i take -2, hence |2| < 1 , NO... Isnt this sufficient?
Should i also consider 0 for X< 3 , which would be |0| < 1, Yes.. hence insufficient ??


How do igo forward for statement 2?

And how does Statement (1)+ (2) give x = 1/3 ??

Regards,
Mustu


Top 
 Post subject: Re: MGMAT Tought Question Bank Problem - Equations, Inequalities
 Post Posted: Fri Aug 12, 2011 11:01 pm 
Offline
ManhattanGMAT Staff


Posts: 2242
Location: Southwest Airlines, seat 21C
For statement 2 you just need to plug in something between -1 and 1, as you did with 0. Once you have the two statements together, here's what you know:

it's either 1/3 or 3
AND
it's not 3

this means it has to be 1/3, so we know that |x|<1

_________________
Tim Sanders
Manhattan GMAT Instructor


Top 
Display posts from previous:  Sort by  
 
 Page 1 of 1 [ 5 posts ] 





Who is online

Users browsing this forum: No registered users and 0 guests

 
 

 
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
Jump to: