Great question!
Quote:
Answer: From the sixth to the one hundredth there are 94 jumps of 3.
94 x3 = 282.
32 + 282 = 314.
To get the 94 jumps I'm guessing you subtract 100-6 = 94.
This method counts the jump
between terms, so you can just subtract the starting term from the ending term.
The add-one-before-you're-done rule applies when you are counting
the terms themselves. If you subtract the starting term from the ending term, you would fail to count that starting term, so you add 1 to account for it.
A real life example: Imagine you are climbing stairs, and each step is numbered with a consecutive integer. You stand on step 1 to begin, and will climb to step 10.
How many steps up will you take? (i.e. how many "jumps" between terms?) 10-1 = 9.
How many steps did you touch? (i.e. how many terms in the sequence?) 10-1+1 = 10. This makes sense, as you touched steps 1 and 10 (and all in between), so 10 steps total.