Register    Login    Search    Rss Feeds

 Page 1 of 1 [ 6 posts ] 



 
Author Message
 Post subject: math
 Post Posted: Thu Sep 06, 2007 10:15 pm 
Question Bank, Inequalities, # 10

If r is not equal to 0, is r^2/|r|<1?


(1) r > -1

(2) r < 1

(1) AND (2) SUFFICIENT: Together, the statements tell us that r is between -1 and 1. The square of a proper fraction (positive or negative) will always be smaller than the absolute value of that proper fraction.

The correct answer is C.
why in this question is not possible the following when c is the answer if r=1/2 then r^2=1/2^2=1/4 then lrl = to -1/2 (since from an absolute value we have positive and negative ) then result = 1/4>-1/2 . I understand when r=-1/2 then r^2=-1/2^2 = 1/4 and lrl=1/2 then this gives us 1/4<1/2


Top 
 Post subject:
 Post Posted: Sun Sep 09, 2007 4:57 pm 
Offline
ManhattanGMAT Staff


Posts: 6917
Location: San Francisco
Quote:
why in this question is not possible the following when c is the answer if r=1/2 then r^2=1/2^2=1/4 then lrl = to -1/2 (since from an absolute value we have positive and negative ) then result = 1/4>-1/2 . I understand when r=-1/2 then r^2=-1/2^2 = 1/4 and lrl=1/2 then this gives us 1/4<1/2


A variable inside an absolute value does mean that the variable could be positive or negative, but you start your question by saying "if r = 1/2" - so you've just set that variable to be positive 1/2, not negative 1/2. You have to keep using that value for r throughout the problem once you set it.

_________________
Stacey Koprince
Instructor
Director of Online Community
ManhattanGMAT


Top 
 Post subject: Re: math
 Post Posted: Thu May 26, 2011 7:47 am 
Offline
Students


Posts: 9
Hi,

I am having a hard time understanding how from

r^2 < |r|

we arrived at the conclusion that ---------------> -1<r<1

What approach is to be used in arriving at the conclusion above? An algebraic approach or an approach of plugging numbers will be more useful?

Thanks


Top 
 Post subject: Re: math
 Post Posted: Sat May 28, 2011 3:19 pm 
Offline
ManhattanGMAT Staff


Posts: 2412
raheel11 wrote:
Hi,

I am having a hard time understanding how from

r^2 < |r|

we arrived at the conclusion that ---------------> -1<r<1

What approach is to be used in arriving at the conclusion above? An algebraic approach or an approach of plugging numbers will be more useful?

Thanks


Think about it this way . . . most numbers when squared become larger. For example, 5 squared is 25. So in this case, we need to think about which numbers become smaller when squared. The first thought that should occur to you is fractions between 0 and 1. For example, 1/2 squared is 1/4.

Now, we may have one other possibility since the denominator has the absolute value of r. What if I square a number between -1 and 0? Well, the squaring will make that number positive, but it will still be smaller than the absolute value of that number (since that particular value will be positive). For example, -1/2 squared is 1/4, and the absolute value of -1/2 is 1/2. So these numbers fit too.

Personally, I think the knowledge that fractions between 0 and 1 become smaller when squared is all the information you need to solve, and then you can just test numbers from there to help you include -1 to 0. Much better than algebra!

_________________
Jamie Nelson
ManhattanGMAT Instructor


Top 
 Post subject: Re: math
 Post Posted: Sun Jun 19, 2011 10:00 am 
Offline
Students


Posts: 9
jnelson0612 wrote:
raheel11 wrote:
Hi,

I am having a hard time understanding how from

r^2 < |r|

we arrived at the conclusion that ---------------> -1<r<1

What approach is to be used in arriving at the conclusion above? An algebraic approach or an approach of plugging numbers will be more useful?

Thanks


Think about it this way . . . most numbers when squared become larger. For example, 5 squared is 25. So in this case, we need to think about which numbers become smaller when squared. The first thought that should occur to you is fractions between 0 and 1. For example, 1/2 squared is 1/4.

Now, we may have one other possibility since the denominator has the absolute value of r. What if I square a number between -1 and 0? Well, the squaring will make that number positive, but it will still be smaller than the absolute value of that number (since that particular value will be positive). For example, -1/2 squared is 1/4, and the absolute value of -1/2 is 1/2. So these numbers fit too.

Personally, I think the knowledge that fractions between 0 and 1 become smaller when squared is all the information you need to solve, and then you can just test numbers from there to help you include -1 to 0. Much better than algebra!



Thank you! That was helpful.


Top 
 Post subject: Re: math
 Post Posted: Sun Jun 19, 2011 11:12 pm 
Offline
ManhattanGMAT Staff


Posts: 2412
Good to hear! :-)

_________________
Jamie Nelson
ManhattanGMAT Instructor


Top 
Display posts from previous:  Sort by  
 
 Page 1 of 1 [ 6 posts ] 





Who is online

Users browsing this forum: No registered users and 0 guests

 
 

 
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
Jump to: