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| Lining up A to H, from M-GAMT CAT |
| Re: Lining up A to H, from M-GAMT CAT |
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Ron Purewal
MGMAT STAFF
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first off, here's a post i made on another forum about this problem, which is farly comprehensive. check it out:
http://www.beatthegmat.com/consecutive-integers-t9838.html now for a couple of your comments:
try this: take a number line, and just put zero, a, and g on it: -------- 0 --------- a ----------- g --------------- note that 'a' is the distance between 0 and a, and 'g' is the distance from 0 to g. so: (0 to g) minus (a to g) should equal (0 to a) therefore (g) minus (a to g) should equal (a) the same is true even when a, g, or both are to the left of zero; try it and you'll see.
because that's not keeping a constant distance between numbers. analogy: think about 10^2, 10^3, and 10^4, which are 100, 1000, and 10,000 respectively. the distance between the first two is only 900, but the latter two are 9000 apart. nowhere close to the same distance. same goes for the powers of five in this problem. (incidentally, the numbers you're trying to use do form a geometric series - not an arithmetic series - but that's irrelevant to this problem) hth |
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| Lining up A to H, from M-GAMT CAT |
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