Anonymous wrote:
I don't know what answer is given to you. But I would go for (B)
Here's why:
* N is divisible by 3. Therefore for a non-zero N, (N + 1) is even and hence N*(N + 1) is divisible by (3*2) i.e. 6. If N = 0, N*(N + 1) = 0 and hence is still divisible by 6 (if 0 is divisible by 3, it is also divisible by 6). Sufficient
* N is even. Here (N+1) is odd, but not necessarily divisible by 3. e.g. if N = 4, N + 1 = 5 and N*(N + 1) is not divisible by 6. However, if N = 2, N + 1 = 3 and N*(N + 1) is divisible by 6. So, not sufficient
Oh ho!!! I see where I was wrong, thank you very much!!! What a silly mistake...
Thanks a ton!!
Saurabh Malpani