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apoorva_srivastva
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Post subject: Is |x|<1? Posted: Thu May 21, 2009 2:22 am |
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Posts: 27
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Is |x|<1?
1.) |x+1| = 2 |x-1| 2.) |x-3| not equal to 3
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I would like to know that if there is mod sign on both the sides of the linear equation ....can we get rid of the mod and slove the equation as a normal linear equation as in statement 1
|x + 1| = 2|x - 1|
so by my logic can we get rid of the mod sign
(x+1) = 2(x-1)
and slove further.....
ALSO PLEASE SUGGEST ME ANY PREP MATERIAL FOR MODULUS AND INEQUALITIES
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StaceyKoprince
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Post subject: Re: Is |x|<1? Posted: Thu May 28, 2009 2:05 pm |
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| ManhattanGMAT Staff |
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Posts: 6077 Location: San Francisco
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The equation you offer is one possibility, but it is not the only possibility - the absolute value sign introduces multiple possible equations that all have to be checked (since this is a DS question).
You can find more material on general absolute values in the Number Properties book and on absolute value equations in the Equations, Inequalities and VICs book.
_________________ Stacey Koprince Instructor Director of Online Community ManhattanGMAT
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